Search a number
-
+
51100544531 is a prime number
BaseRepresentation
bin101111100101110101…
…000110111000010011
311212220021200121220102
4233211311012320103
51314123214411111
635250354003015
73456214314251
oct574565067023
9155807617812
1051100544531
111a742a1a493
129aa157646b
134a84a814ca
14268a9715d1
1514e12d713b
hexbe5d46e13

51100544531 has 2 divisors, whose sum is σ = 51100544532. Its totient is φ = 51100544530.

The previous prime is 51100544471. The next prime is 51100544533. The reversal of 51100544531 is 13544500115.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51100544531 is a prime.

It is a super-2 number, since 2×511005445312 (a number of 22 digits) contains 22 as substring.

Together with 51100544533, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 51100544494 and 51100544503.

It is not a weakly prime, because it can be changed into another prime (51100544533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25550272265 + 25550272266.

It is an arithmetic number, because the mean of its divisors is an integer number (25550272266).

Almost surely, 251100544531 is an apocalyptic number.

51100544531 is a deficient number, since it is larger than the sum of its proper divisors (1).

51100544531 is an equidigital number, since it uses as much as digits as its factorization.

51100544531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6000, while the sum is 29.

The spelling of 51100544531 in words is "fifty-one billion, one hundred million, five hundred forty-four thousand, five hundred thirty-one".