Base | Representation |
---|---|
bin | 101111100101111011… |
… | …100111010101101111 |
3 | 11212220101220021211221 |
4 | 233211323213111233 |
5 | 1314124134002401 |
6 | 35250454324211 |
7 | 3456234650425 |
oct | 574573472557 |
9 | 155811807757 |
10 | 51102250351 |
11 | 1a743985059 |
12 | 9aa2059667 |
13 | 4a8522aa79 |
14 | 268ac97115 |
15 | 14e15227a1 |
hex | be5ee756f |
51102250351 has 4 divisors (see below), whose sum is σ = 51249519432. Its totient is φ = 50954981272.
The previous prime is 51102250301. The next prime is 51102250369. The reversal of 51102250351 is 15305220115.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15305220115 = 5 ⋅3061044023.
It is a cyclic number.
It is not a de Polignac number, because 51102250351 - 29 = 51102249839 is a prime.
It is a super-2 number, since 2×511022503512 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51102250301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73634020 + ... + 73634713.
It is an arithmetic number, because the mean of its divisors is an integer number (12812379858).
Almost surely, 251102250351 is an apocalyptic number.
51102250351 is a deficient number, since it is larger than the sum of its proper divisors (147269081).
51102250351 is a wasteful number, since it uses less digits than its factorization.
51102250351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 147269080.
The product of its (nonzero) digits is 1500, while the sum is 25.
Adding to 51102250351 its reverse (15305220115), we get a palindrome (66407470466).
The spelling of 51102250351 in words is "fifty-one billion, one hundred two million, two hundred fifty thousand, three hundred fifty-one".
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