Base | Representation |
---|---|
bin | 101111100110100011… |
… | …110101011110110001 |
3 | 11212221010201222001200 |
4 | 233212203311132301 |
5 | 1314134333402113 |
6 | 35251512321413 |
7 | 3456423403140 |
oct | 574643653661 |
9 | 155833658050 |
10 | 51112794033 |
11 | 1a749926744 |
12 | 9aa56a3269 |
13 | 4a8747cc32 |
14 | 268c43d757 |
15 | 14e2406873 |
hex | be68f57b1 |
51112794033 has 24 divisors (see below), whose sum is σ = 86434647936. Its totient is φ = 28494936000.
The previous prime is 51112794013. The next prime is 51112794049. The reversal of 51112794033 is 33049721115.
51112794033 is a `hidden beast` number, since 511 + 1 + 2 + 79 + 40 + 33 = 666.
It is not a de Polignac number, because 51112794033 - 25 = 51112794001 is a prime.
It is a super-2 number, since 2×511127940332 (a number of 22 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (51112794013) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9891493 + ... + 9896658.
It is an arithmetic number, because the mean of its divisors is an integer number (3601443664).
Almost surely, 251112794033 is an apocalyptic number.
It is an amenable number.
51112794033 is a deficient number, since it is larger than the sum of its proper divisors (35321853903).
51112794033 is a wasteful number, since it uses less digits than its factorization.
51112794033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19788205 (or 19788202 counting only the distinct ones).
The product of its (nonzero) digits is 22680, while the sum is 36.
The spelling of 51112794033 in words is "fifty-one billion, one hundred twelve million, seven hundred ninety-four thousand, thirty-three".
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