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51131120150035 = 547217579234681
BaseRepresentation
bin10111010000000111001000…
…10000001110011000010011
320201001002100200021110020001
423220003210100032120103
523200213013224300120
6300425151243430431
713525046552153062
oct1350034420163023
9221032320243201
1051131120150035
111532364a380442
125899678825417
13226b84a97a7c3
14c8aa8bbc21d9
155da087750e0a
hex2e80e440e613

51131120150035 has 8 divisors (see below), whose sum is σ = 62662819588416. Its totient is φ = 40034579181120.

The previous prime is 51131120150023. The next prime is 51131120150083. The reversal of 51131120150035 is 53005102113115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 51131120150035 - 239 = 50581364336147 is a prime.

It is a super-2 number, since 2×511311201500352 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51131120149985 and 51131120150012.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 108789617106 + ... + 108789617575.

It is an arithmetic number, because the mean of its divisors is an integer number (7832852448552).

Almost surely, 251131120150035 is an apocalyptic number.

51131120150035 is a deficient number, since it is larger than the sum of its proper divisors (11531699438381).

51131120150035 is a wasteful number, since it uses less digits than its factorization.

51131120150035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 217579234733.

The product of its (nonzero) digits is 2250, while the sum is 28.

The spelling of 51131120150035 in words is "fifty-one trillion, one hundred thirty-one billion, one hundred twenty million, one hundred fifty thousand, thirty-five".

Divisors: 1 5 47 235 217579234681 1087896173405 10226224030007 51131120150035