Base | Representation |
---|---|
bin | 110000010010011100… |
… | …001111010111000111 |
3 | 11221211110001010022211 |
4 | 300102130033113013 |
5 | 1322141321003031 |
6 | 35452532004251 |
7 | 3513603142306 |
oct | 602234172707 |
9 | 157743033284 |
10 | 51849000391 |
11 | 1aa97455451 |
12 | a070160687 |
13 | 4b73b581b6 |
14 | 271c12043d |
15 | 1536d7bbb1 |
hex | c1270f5c7 |
51849000391 has 4 divisors (see below), whose sum is σ = 51897503800. Its totient is φ = 51800496984.
The previous prime is 51849000377. The next prime is 51849000407. The reversal of 51849000391 is 19300094815.
51849000391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51849000391 - 27 = 51849000263 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51849000341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24250101 + ... + 24252238.
It is an arithmetic number, because the mean of its divisors is an integer number (12974375950).
Almost surely, 251849000391 is an apocalyptic number.
51849000391 is the 144013-rd centered pentagonal number.
51849000391 is a deficient number, since it is larger than the sum of its proper divisors (48503409).
51849000391 is a wasteful number, since it uses less digits than its factorization.
51849000391 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48503408.
The product of its (nonzero) digits is 38880, while the sum is 40.
The spelling of 51849000391 in words is "fifty-one billion, eight hundred forty-nine million, three hundred ninety-one", and thus it is an aban number.
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