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51849000391 = 106948502339
BaseRepresentation
bin110000010010011100…
…001111010111000111
311221211110001010022211
4300102130033113013
51322141321003031
635452532004251
73513603142306
oct602234172707
9157743033284
1051849000391
111aa97455451
12a070160687
134b73b581b6
14271c12043d
151536d7bbb1
hexc1270f5c7

51849000391 has 4 divisors (see below), whose sum is σ = 51897503800. Its totient is φ = 51800496984.

The previous prime is 51849000377. The next prime is 51849000407. The reversal of 51849000391 is 19300094815.

51849000391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 51849000391 - 27 = 51849000263 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51849000341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24250101 + ... + 24252238.

It is an arithmetic number, because the mean of its divisors is an integer number (12974375950).

Almost surely, 251849000391 is an apocalyptic number.

51849000391 is the 144013-rd centered pentagonal number.

51849000391 is a deficient number, since it is larger than the sum of its proper divisors (48503409).

51849000391 is a wasteful number, since it uses less digits than its factorization.

51849000391 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48503408.

The product of its (nonzero) digits is 38880, while the sum is 40.

The spelling of 51849000391 in words is "fifty-one billion, eight hundred forty-nine million, three hundred ninety-one", and thus it is an aban number.

Divisors: 1 1069 48502339 51849000391