Base | Representation |
---|---|
bin | 10111110011010100111111… |
… | …11001000010110100000101 |
3 | 20212022202200000102221221012 |
4 | 23321222133321002310011 |
5 | 23330024140411001013 |
6 | 303153105540332005 |
7 | 14011344406163315 |
oct | 1371523771026405 |
9 | 225282600387835 |
10 | 52341154000133 |
11 | 1574a8389a1629 |
12 | 5a540966a4005 |
13 | 2328998c751cb |
14 | ccd47ab61445 |
15 | 60b7a82841a8 |
hex | 2f9a9fe42d05 |
52341154000133 has 16 divisors (see below), whose sum is σ = 52589131655424. Its totient is φ = 52093827717120.
The previous prime is 52341154000129. The next prime is 52341154000151. The reversal of 52341154000133 is 33100045114325.
It is a cyclic number.
It is not a de Polignac number, because 52341154000133 - 22 = 52341154000129 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 52341154000133.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52341154000153) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 708741416 + ... + 708815262.
It is an arithmetic number, because the mean of its divisors is an integer number (3286820728464).
Almost surely, 252341154000133 is an apocalyptic number.
It is an amenable number.
52341154000133 is a deficient number, since it is larger than the sum of its proper divisors (247977655291).
52341154000133 is a wasteful number, since it uses less digits than its factorization.
52341154000133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 78212.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 52341154000133 its reverse (33100045114325), we get a palindrome (85441199114458).
The spelling of 52341154000133 in words is "fifty-two trillion, three hundred forty-one billion, one hundred fifty-four million, one hundred thirty-three", and thus it is an aban number.
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