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52473000631 = 353379392213
BaseRepresentation
bin110000110111101000…
…100111001010110111
312000102221012121201211
4300313220213022313
51324431042010011
640034502302251
73535221101062
oct606750471267
9160387177654
1052473000631
1120287706027
12a205127987
134c43207bcc
14277ad538d9
151571a3ab21
hexc37a272b7

52473000631 has 8 divisors (see below), whose sum is σ = 52760627280. Its totient is φ = 52186159872.

The previous prime is 52473000589. The next prime is 52473000691. The reversal of 52473000631 is 13600037425.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 52473000631 - 215 = 52472967863 is a prime.

It is a super-2 number, since 2×524730006312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 52473000593 and 52473000602.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52473000691) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62320 + ... + 329893.

It is an arithmetic number, because the mean of its divisors is an integer number (6595078410).

Almost surely, 252473000631 is an apocalyptic number.

52473000631 is the 144877-th centered pentagonal number.

52473000631 is a deficient number, since it is larger than the sum of its proper divisors (287626649).

52473000631 is a wasteful number, since it uses less digits than its factorization.

52473000631 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 392945.

The product of its (nonzero) digits is 15120, while the sum is 31.

The spelling of 52473000631 in words is "fifty-two billion, four hundred seventy-three million, six hundred thirty-one", and thus it is an aban number.

Divisors: 1 353 379 133787 392213 138451189 148648727 52473000631