Base | Representation |
---|---|
bin | 111100010000101000110111… |
… | …0010001111100010010100001 |
3 | 2120111202111202220210211022102 |
4 | 1320201101232101330102201 |
5 | 1023433334210124143410 |
6 | 5115154405003420145 |
7 | 216435006314332631 |
oct | 17041215621742241 |
9 | 2514674686724272 |
10 | 530052354131105 |
11 | 143988a3951a473 |
12 | 4b547844b24655 |
13 | 1999b9514bb630 |
14 | 94c6956a566c1 |
15 | 4142d28a822a5 |
hex | 1e2146e47c4a1 |
530052354131105 has 32 divisors (see below), whose sum is σ = 685145199866400. Its totient is φ = 391335019333632.
The previous prime is 530052354131081. The next prime is 530052354131177. The reversal of 530052354131105 is 501131453250035.
It can be written as a sum of positive squares in 16 ways, for example, as 176748941732416 + 353303412398689 = 13294696^2 + 18796367^2 .
It is a cyclic number.
It is not a de Polignac number, because 530052354131105 - 232 = 530048059163809 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9322523837 + ... + 9322580693.
It is an arithmetic number, because the mean of its divisors is an integer number (21410787495825).
Almost surely, 2530052354131105 is an apocalyptic number.
It is an amenable number.
530052354131105 is a deficient number, since it is larger than the sum of its proper divisors (155092845735295).
530052354131105 is a wasteful number, since it uses less digits than its factorization.
530052354131105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86693.
The product of its (nonzero) digits is 135000, while the sum is 38.
The spelling of 530052354131105 in words is "five hundred thirty trillion, fifty-two billion, three hundred fifty-four million, one hundred thirty-one thousand, one hundred five".
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