Base | Representation |
---|---|
bin | 110001011000000011… |
… | …110011100100000001 |
3 | 12001211211211122211202 |
4 | 301120003303210001 |
5 | 1332034323001233 |
6 | 40204454150545 |
7 | 3554545031453 |
oct | 613003634401 |
9 | 161754748752 |
10 | 53017000193 |
11 | 20536794a43 |
12 | a337352455 |
13 | 4ccbb27141 |
14 | 27cd2c02d3 |
15 | 15a4695be8 |
hex | c580f3901 |
53017000193 has 2 divisors, whose sum is σ = 53017000194. Its totient is φ = 53017000192.
The previous prime is 53017000187. The next prime is 53017000217. The reversal of 53017000193 is 39100071035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 43069531024 + 9947469169 = 207532^2 + 99737^2 .
It is a cyclic number.
It is not a de Polignac number, because 53017000193 - 214 = 53016983809 is a prime.
It is a weakly prime.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26508500096 + 26508500097.
It is an arithmetic number, because the mean of its divisors is an integer number (26508500097).
Almost surely, 253017000193 is an apocalyptic number.
It is an amenable number.
53017000193 is a deficient number, since it is larger than the sum of its proper divisors (1).
53017000193 is an equidigital number, since it uses as much as digits as its factorization.
53017000193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2835, while the sum is 29.
The spelling of 53017000193 in words is "fifty-three billion, seventeen million, one hundred ninety-three", and thus it is an aban number.
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