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53025041 = 163325307
BaseRepresentation
bin1100101001000…
…1100100010001
310200202221200102
43022101210101
5102033300131
65132302145
71212463646
oct312214421
9120687612
1053025041
1127a27553
1215911955
13aca7284
147083dcd
1549c61cb
hex3291911

53025041 has 4 divisors (see below), whose sum is σ = 53350512. Its totient is φ = 52699572.

The previous prime is 53025031. The next prime is 53025053. The reversal of 53025041 is 14052035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14052035 = 52810407.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53025041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53025031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162491 + ... + 162816.

It is an arithmetic number, because the mean of its divisors is an integer number (13337628).

Almost surely, 253025041 is an apocalyptic number.

It is an amenable number.

53025041 is a deficient number, since it is larger than the sum of its proper divisors (325471).

53025041 is a wasteful number, since it uses less digits than its factorization.

53025041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 325470.

The product of its (nonzero) digits is 600, while the sum is 20.

The square root of 53025041 is about 7281.8295091275. The cubic root of 53025041 is about 375.6877240647.

Adding to 53025041 its reverse (14052035), we get a palindrome (67077076).

The spelling of 53025041 in words is "fifty-three million, twenty-five thousand, forty-one".

Divisors: 1 163 325307 53025041