Base | Representation |
---|---|
bin | 110001011010011100… |
… | …111011111101001011 |
3 | 12001221122101002212200 |
4 | 301122130323331023 |
5 | 1332130112030403 |
6 | 40212450411243 |
7 | 3555543161643 |
oct | 613234737513 |
9 | 161848332780 |
10 | 53057142603 |
11 | 20557412593 |
12 | a348890b23 |
13 | 500724074a |
14 | 27d476d523 |
15 | 15a7e74ca3 |
hex | c5a73bf4b |
53057142603 has 12 divisors (see below), whose sum is σ = 77894457888. Its totient is φ = 34791568560.
The previous prime is 53057142583. The next prime is 53057142623. The reversal of 53057142603 is 30624175035.
53057142603 is a `hidden beast` number, since 5 + 3 + 0 + 5 + 7 + 1 + 42 + 603 = 666.
It is an interprime number because it is at equal distance from previous prime (53057142583) and next prime (53057142623).
It is not a de Polignac number, because 53057142603 - 26 = 53057142539 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53057142623) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 48321075 + ... + 48322172.
It is an arithmetic number, because the mean of its divisors is an integer number (6491204824).
Almost surely, 253057142603 is an apocalyptic number.
53057142603 is a deficient number, since it is larger than the sum of its proper divisors (24837315285).
53057142603 is a wasteful number, since it uses less digits than its factorization.
53057142603 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96643314 (or 96643311 counting only the distinct ones).
The product of its (nonzero) digits is 75600, while the sum is 36.
The spelling of 53057142603 in words is "fifty-three billion, fifty-seven million, one hundred forty-two thousand, six hundred three".
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