Base | Representation |
---|---|
bin | 110001011101000111… |
… | …111111010110000001 |
3 | 12002001202202020111000 |
4 | 301131013333112001 |
5 | 1332223101424410 |
6 | 40221131442213 |
7 | 3556626260163 |
oct | 613507772601 |
9 | 162052666430 |
10 | 53101983105 |
11 | 2057a759956 |
12 | a35b8b6369 |
13 | 50136105a2 |
14 | 27da6c2933 |
15 | 15abd80dc0 |
hex | c5d1ff581 |
53101983105 has 64 divisors (see below), whose sum is σ = 101364825600. Its totient is φ = 26279608320.
The previous prime is 53101983083. The next prime is 53101983239. The reversal of 53101983105 is 50138910135.
53101983105 is a `hidden beast` number, since 531 + 0 + 1 + 98 + 31 + 0 + 5 = 666.
53101983105 is a nontrivial binomial coefficient, being equal to C(325890, 2).
It is not a de Polignac number, because 53101983105 - 27 = 53101982977 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53101983105.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1 + ... + 325889.
It is an arithmetic number, because the mean of its divisors is an integer number (1583825400).
Almost surely, 253101983105 is an apocalyptic number.
53101983105 is the 325889-th triangular number and also the 162945-th hexagonal number.
It is an amenable number.
53101983105 is a deficient number, since it is larger than the sum of its proper divisors (48262842495).
53101983105 is a wasteful number, since it uses less digits than its factorization.
With its predecessor (53101983104) it forms a Ruth-Aaron pair, since the sum of their prime factors is the same (325991).
53101983105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 325991 (or 325985 counting only the distinct ones).
The product of its (nonzero) digits is 16200, while the sum is 36.
The spelling of 53101983105 in words is "fifty-three billion, one hundred one million, nine hundred eighty-three thousand, one hundred five".
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