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BaseRepresentation
bin1100101010100…
…0110010010101
310200221210010221
43022220302111
5102044321044
65134314341
71213341145
oct312506225
9120853127
1053120149
1127a91a55
12159589b1
13b00b654
1470aa925
1549e4484
hex32a8c95

53120149 has 4 divisors (see below), whose sum is σ = 53145664. Its totient is φ = 53094636.

The previous prime is 53120117. The next prime is 53120173. The reversal of 53120149 is 94102135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 94102135 = 518820427.

It is a cyclic number.

It is not a de Polignac number, because 53120149 - 25 = 53120117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53120449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9327 + ... + 13900.

It is an arithmetic number, because the mean of its divisors is an integer number (13286416).

It is a 2082-hyperperfect number.

Almost surely, 253120149 is an apocalyptic number.

It is an amenable number.

53120149 is a deficient number, since it is larger than the sum of its proper divisors (25515).

53120149 is a wasteful number, since it uses less digits than its factorization.

53120149 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25514.

The product of its (nonzero) digits is 1080, while the sum is 25.

The square root of 53120149 is about 7288.3570851050. The cubic root of 53120149 is about 375.9122064716.

The spelling of 53120149 in words is "fifty-three million, one hundred twenty thousand, one hundred forty-nine".

Divisors: 1 2287 23227 53120149