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5312140135 = 53728714271
BaseRepresentation
bin1001111001010000…
…01101001101100111
3111201012201200022221
410330220031031213
541334401441020
62235041333211
7245432306011
oct47450151547
914635650287
105312140135
112286623565
121043037207
1366871a3b3
143857151b1
152115626aa
hex13ca0d367

5312140135 has 8 divisors (see below), whose sum is σ = 6546854016. Its totient is φ = 4134854880.

The previous prime is 5312140121. The next prime is 5312140153. The reversal of 5312140135 is 5310412135.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-5312140135 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14356951 + ... + 14357320.

It is an arithmetic number, because the mean of its divisors is an integer number (818356752).

Almost surely, 25312140135 is an apocalyptic number.

5312140135 is a deficient number, since it is larger than the sum of its proper divisors (1234713881).

5312140135 is a wasteful number, since it uses less digits than its factorization.

5312140135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28714313.

The product of its (nonzero) digits is 1800, while the sum is 25.

The square root of 5312140135 is about 72884.4299902249. The cubic root of 5312140135 is about 1744.8436117897.

Subtracting from 5312140135 its reverse (5310412135), we obtain a cube (1728000 = 1203).

The spelling of 5312140135 in words is "five billion, three hundred twelve million, one hundred forty thousand, one hundred thirty-five".

Divisors: 1 5 37 185 28714271 143571355 1062428027 5312140135