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53125254331 = 401132481931
BaseRepresentation
bin110001011110100000…
…110000110010111011
312002010101112112121021
4301132200300302323
51332300031114311
640223322323311
73560331132262
oct613640606273
9162111475537
1053125254331
1120591903976
12a367659537
13501839a946
1427dd81d5d9
1515ade2b171
hexc5e830cbb

53125254331 has 4 divisors (see below), whose sum is σ = 53257736664. Its totient is φ = 52992772000.

The previous prime is 53125254307. The next prime is 53125254359. The reversal of 53125254331 is 13345252135.

53125254331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53125254331 - 223 = 53116865723 is a prime.

It is a super-2 number, since 2×531252543312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53125254431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66240565 + ... + 66241366.

It is an arithmetic number, because the mean of its divisors is an integer number (13314434166).

Almost surely, 253125254331 is an apocalyptic number.

53125254331 is a deficient number, since it is larger than the sum of its proper divisors (132482333).

53125254331 is a wasteful number, since it uses less digits than its factorization.

53125254331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 132482332.

The product of its digits is 54000, while the sum is 34.

The spelling of 53125254331 in words is "fifty-three billion, one hundred twenty-five million, two hundred fifty-four thousand, three hundred thirty-one".

Divisors: 1 401 132481931 53125254331