53125254431 has 2 divisors, whose sum is σ = 53125254432. Its totient is φ = 53125254430.

The previous prime is 53125254397. The next prime is 53125254451. The reversal of 53125254431 is 13445252135.

53125254431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 53125254431 - 2¹⁰ = 53125253407 is a prime.

It is a super-2 number, since 2×53125254431² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53125254391 and 53125254400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53125254451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26562627215 + 26562627216.

It is an arithmetic number, because the mean of its divisors is an integer number (26562627216).

Almost surely, 2^53125254431 is an apocalyptic number.

53125254431 is a deficient number, since it is larger than the sum of its proper divisors (1).

53125254431 is an equidigital number, since it uses as much as digits as its factorization.

53125254431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 72000, while the sum is 35.

The spelling of 53125254431 in words is "fifty-three billion, one hundred twenty-five million, two hundred fifty-four thousand, four hundred thirty-one".