Base | Representation |
---|---|
bin | 100110101111101101100… |
… | …1001010011101100100011 |
3 | 200212002010020111212221222 |
4 | 1031133123021103230203 |
5 | 1144221342112130034 |
6 | 15154200331205255 |
7 | 1056504650523614 |
oct | 115373311235443 |
9 | 20762106455858 |
10 | 5325141130019 |
11 | 177341a383967 |
12 | 72006aba682b |
13 | 2c820a740b69 |
14 | 145a498cbc0b |
15 | 937bc17e12e |
hex | 4d7db253b23 |
5325141130019 has 2 divisors, whose sum is σ = 5325141130020. Its totient is φ = 5325141130018.
The previous prime is 5325141130007. The next prime is 5325141130069. The reversal of 5325141130019 is 9100311415235.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5325141130019 is a prime.
It is a super-2 number, since 2×53251411300192 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5325141130069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2662570565009 + 2662570565010.
It is an arithmetic number, because the mean of its divisors is an integer number (2662570565010).
Almost surely, 25325141130019 is an apocalyptic number.
5325141130019 is a deficient number, since it is larger than the sum of its proper divisors (1).
5325141130019 is an equidigital number, since it uses as much as digits as its factorization.
5325141130019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16200, while the sum is 35.
The spelling of 5325141130019 in words is "five trillion, three hundred twenty-five billion, one hundred forty-one million, one hundred thirty thousand, nineteen".
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