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5334414031043 is a prime number
BaseRepresentation
bin100110110100000001111…
…0110100111100011000011
3200212222001111010001210122
41031220003312213203003
51144344334442443133
615202332421450455
71060253516060516
oct115500366474303
920788044101718
105334414031043
11177734871a729
12721a18570a2b
132c90578c1546
14146289260d7d
1593b612b5498
hex4da03da78c3

5334414031043 has 2 divisors, whose sum is σ = 5334414031044. Its totient is φ = 5334414031042.

The previous prime is 5334414031003. The next prime is 5334414031081. The reversal of 5334414031043 is 3401304144335.

5334414031043 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5334414031043 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5334414030994 and 5334414031012.

It is not a weakly prime, because it can be changed into another prime (5334414031003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667207015521 + 2667207015522.

It is an arithmetic number, because the mean of its divisors is an integer number (2667207015522).

Almost surely, 25334414031043 is an apocalyptic number.

5334414031043 is a deficient number, since it is larger than the sum of its proper divisors (1).

5334414031043 is an equidigital number, since it uses as much as digits as its factorization.

5334414031043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 5334414031043 its reverse (3401304144335), we get a palindrome (8735718175378).

The spelling of 5334414031043 in words is "five trillion, three hundred thirty-four billion, four hundred fourteen million, thirty-one thousand, forty-three".