Base | Representation |
---|---|
bin | 100110111000000100110… |
… | …1010011011110100010001 |
3 | 200220210110220222220212102 |
4 | 1031300021222123310101 |
5 | 1200020132431411103 |
6 | 15210330435010145 |
7 | 1061012014561346 |
oct | 115601152336421 |
9 | 20823426886772 |
10 | 5343101435153 |
11 | 177aaa6513a49 |
12 | 723641a39955 |
13 | 2c9b10683751 |
14 | 146870d447cd |
15 | 93ebdce5e88 |
hex | 4dc09a9bd11 |
5343101435153 has 2 divisors, whose sum is σ = 5343101435154. Its totient is φ = 5343101435152.
The previous prime is 5343101435129. The next prime is 5343101435179. The reversal of 5343101435153 is 3515341013435.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4238727439489 + 1104373995664 = 2058817^2 + 1050892^2 .
It is a cyclic number.
It is not a de Polignac number, because 5343101435153 - 228 = 5342832999697 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (5343101435183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2671550717576 + 2671550717577.
It is an arithmetic number, because the mean of its divisors is an integer number (2671550717577).
Almost surely, 25343101435153 is an apocalyptic number.
It is an amenable number.
5343101435153 is a deficient number, since it is larger than the sum of its proper divisors (1).
5343101435153 is an equidigital number, since it uses as much as digits as its factorization.
5343101435153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 38.
Adding to 5343101435153 its reverse (3515341013435), we get a palindrome (8858442448588).
The spelling of 5343101435153 in words is "five trillion, three hundred forty-three billion, one hundred one million, four hundred thirty-five thousand, one hundred fifty-three".
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