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5343101435153 is a prime number
BaseRepresentation
bin100110111000000100110…
…1010011011110100010001
3200220210110220222220212102
41031300021222123310101
51200020132431411103
615210330435010145
71061012014561346
oct115601152336421
920823426886772
105343101435153
11177aaa6513a49
12723641a39955
132c9b10683751
14146870d447cd
1593ebdce5e88
hex4dc09a9bd11

5343101435153 has 2 divisors, whose sum is σ = 5343101435154. Its totient is φ = 5343101435152.

The previous prime is 5343101435129. The next prime is 5343101435179. The reversal of 5343101435153 is 3515341013435.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4238727439489 + 1104373995664 = 2058817^2 + 1050892^2 .

It is a cyclic number.

It is not a de Polignac number, because 5343101435153 - 228 = 5342832999697 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (5343101435183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2671550717576 + 2671550717577.

It is an arithmetic number, because the mean of its divisors is an integer number (2671550717577).

Almost surely, 25343101435153 is an apocalyptic number.

It is an amenable number.

5343101435153 is a deficient number, since it is larger than the sum of its proper divisors (1).

5343101435153 is an equidigital number, since it uses as much as digits as its factorization.

5343101435153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162000, while the sum is 38.

Adding to 5343101435153 its reverse (3515341013435), we get a palindrome (8858442448588).

The spelling of 5343101435153 in words is "five trillion, three hundred forty-three billion, one hundred one million, four hundred thirty-five thousand, one hundred fifty-three".