Base | Representation |
---|---|
bin | 110001110001001010… |
… | …001110010111001101 |
3 | 12002221012020102022212 |
4 | 301301022032113031 |
5 | 1333420124110404 |
6 | 40314340120205 |
7 | 3601150316324 |
oct | 616112162715 |
9 | 162835212285 |
10 | 53438113229 |
11 | 20732470446 |
12 | a434396065 |
13 | 506814b657 |
14 | 282d1bd0bb |
15 | 15cb62a06e |
hex | c7128e5cd |
53438113229 has 2 divisors, whose sum is σ = 53438113230. Its totient is φ = 53438113228.
The previous prime is 53438113219. The next prime is 53438113231. The reversal of 53438113229 is 92231183435.
53438113229 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 40884031204 + 12554082025 = 202198^2 + 112045^2 .
It is a cyclic number.
It is not a de Polignac number, because 53438113229 - 212 = 53438109133 is a prime.
It is a Sophie Germain prime.
Together with 53438113231, it forms a pair of twin primes.
It is a Chen prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53438113219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26719056614 + 26719056615.
It is an arithmetic number, because the mean of its divisors is an integer number (26719056615).
Almost surely, 253438113229 is an apocalyptic number.
It is an amenable number.
53438113229 is a deficient number, since it is larger than the sum of its proper divisors (1).
53438113229 is an equidigital number, since it uses as much as digits as its factorization.
53438113229 is an evil number, because the sum of its binary digits is even.
The product of its digits is 155520, while the sum is 41.
The spelling of 53438113229 in words is "fifty-three billion, four hundred thirty-eight million, one hundred thirteen thousand, two hundred twenty-nine".
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