Base | Representation |
---|---|
bin | 1100110001000… |
… | …1101111011001 |
3 | 10201202121211212 |
4 | 3030101233121 |
5 | 102202100131 |
6 | 5151432505 |
7 | 1220111366 |
oct | 314215731 |
9 | 121677755 |
10 | 53550041 |
11 | 28255a36 |
12 | 15b25735 |
13 | b12c21c |
14 | 717d46d |
15 | 4a7ba2b |
hex | 3311bd9 |
53550041 has 2 divisors, whose sum is σ = 53550042. Its totient is φ = 53550040.
The previous prime is 53550011. The next prime is 53550067. The reversal of 53550041 is 14005535.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 35952016 + 17598025 = 5996^2 + 4195^2 .
It is a cyclic number.
It is not a de Polignac number, because 53550041 - 210 = 53549017 is a prime.
It is a super-2 number, since 2×535500412 = 5735213782203362, which contains 22 as substring.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 53549989 and 53550016.
It is not a weakly prime, because it can be changed into another prime (53550011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26775020 + 26775021.
It is an arithmetic number, because the mean of its divisors is an integer number (26775021).
Almost surely, 253550041 is an apocalyptic number.
It is an amenable number.
53550041 is a deficient number, since it is larger than the sum of its proper divisors (1).
53550041 is an equidigital number, since it uses as much as digits as its factorization.
53550041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1500, while the sum is 23.
The square root of 53550041 is about 7317.7893519833. The cubic root of 53550041 is about 376.9235468944.
Adding to 53550041 its reverse (14005535), we get a palindrome (67555576).
The spelling of 53550041 in words is "fifty-three million, five hundred fifty thousand, forty-one".
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