53917332480000 has 2800 divisors, whose sum is σ = 224725760937216. Its totient is φ = 12766740480000.

The previous prime is 53917332479999. The next prime is 53917332480001. The reversal of 53917332480000 is 8423371935.

53917332480000 is a `hidden beast` number, since 53 + 91 + 7 + 3 + 32 + 480 + 0 + 0 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (53917332479999) and next prime (53917332480001).

It is a Harshad number since it is a multiple of its sum of digits (45).

It is not an unprimeable number, because it can be changed into a prime (53917332480001) by changing a digit.

It is a polite number, since it can be written in 199 ways as a sum of consecutive naturals, for example, 241781759889 + ... + 241781760111.

Almost surely, 2^{53917332480000} is an apocalyptic number.

53917332480000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 53917332480000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (112362880468608).

53917332480000 is an abundant number, since it is smaller than the sum of its proper divisors (170808428457216).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53917332480000 is an equidigital number, since it uses as much as digits as its factorization.

53917332480000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 345 (or 297 counting only the distinct ones).

The product of its (nonzero) digits is 544320, while the sum is 45.

The spelling of 53917332480000 in words is "fifty-three trillion, nine hundred seventeen billion, three hundred thirty-two million, four hundred eighty thousand".