Base | Representation |
---|---|
bin | 11000100111001001010110… |
… | …11110111010000101110111 |
3 | 21002121222100020001222020020 |
4 | 30103210223132322011313 |
5 | 24043212030234410242 |
6 | 311035043035340223 |
7 | 14254105003064046 |
oct | 1423445336720567 |
9 | 232558306058206 |
10 | 54121612419447 |
11 | 16276935299431 |
12 | 60a116a5b1673 |
13 | 2427852799701 |
14 | d5170009855d |
15 | 63cc624246ec |
hex | 31392b7ba177 |
54121612419447 has 16 divisors (see below), whose sum is σ = 75964839600000. Its totient is φ = 34179964183584.
The previous prime is 54121612419421. The next prime is 54121612419487. The reversal of 54121612419447 is 74491421612145.
It is a de Polignac number, because none of the positive numbers 2k-54121612419447 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 54121612419447.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54121612419487) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28328197 + ... + 30178302.
It is an arithmetic number, because the mean of its divisors is an integer number (4747802475000).
Almost surely, 254121612419447 is an apocalyptic number.
54121612419447 is a gapful number since it is divisible by the number (57) formed by its first and last digit.
54121612419447 is a deficient number, since it is larger than the sum of its proper divisors (21843227180553).
54121612419447 is a wasteful number, since it uses less digits than its factorization.
54121612419447 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58522750.
The product of its digits is 1935360, while the sum is 51.
The spelling of 54121612419447 in words is "fifty-four trillion, one hundred twenty-one billion, six hundred twelve million, four hundred nineteen thousand, four hundred forty-seven".
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