Base | Representation |
---|---|
bin | 100111011000110001111… |
… | …0111101011011011011001 |
3 | 201011111202120120210201120 |
4 | 1032301203313223123121 |
5 | 1202143002042130040 |
6 | 15302503525435453 |
7 | 1066046320424034 |
oct | 116614367533331 |
9 | 21144676523646 |
10 | 5413334333145 |
11 | 17a78671187a2 |
12 | 73518286bb89 |
13 | 30362413345b |
14 | 14a01486401b |
15 | 95c2eaad7d0 |
hex | 4ec63deb6d9 |
5413334333145 has 16 divisors (see below), whose sum is σ = 8661369372480. Its totient is φ = 2887100164544.
The previous prime is 5413334333131. The next prime is 5413334333159.
5413334333145 is nontrivially palindromic in base 10.
It is an interprime number because it is at equal distance from previous prime (5413334333131) and next prime (5413334333159).
It is a cyclic number.
It is not a de Polignac number, because 5413334333145 - 210 = 5413334332121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5413334333097 and 5413334333106.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4322911 + ... + 5432699.
It is an arithmetic number, because the mean of its divisors is an integer number (541335585780).
Almost surely, 25413334333145 is an apocalyptic number.
It is an amenable number.
5413334333145 is a deficient number, since it is larger than the sum of its proper divisors (3248035039335).
5413334333145 is a wasteful number, since it uses less digits than its factorization.
5413334333145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1434984.
The product of its digits is 1166400, while the sum is 42.
The spelling of 5413334333145 in words is "five trillion, four hundred thirteen billion, three hundred thirty-four million, three hundred thirty-three thousand, one hundred forty-five".
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