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5489349331200 = 283527277147449
BaseRepresentation
bin100111111100001011010…
…1101111000100100000000
3201102202222012012210201220
41033320112231320210000
51204414141412044300
615401434450555040
71104410123306130
oct117702655704400
921382865183656
105489349331200
111827024654939
12747a57b98a80
1330a849798347
1414d986270ac0
1597bcd2bada0
hex4fe16b78900

5489349331200 has 432 divisors, whose sum is σ = 20778880483200. Its totient is φ = 1250170306560.

The previous prime is 5489349331181. The next prime is 5489349331201. The reversal of 5489349331200 is 21339439845.

It is not an unprimeable number, because it can be changed into a prime (5489349331201) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 37155076 + ... + 37302524.

Almost surely, 25489349331200 is an apocalyptic number.

5489349331200 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 5489349331200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (10389440241600).

5489349331200 is an abundant number, since it is smaller than the sum of its proper divisors (15289531152000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

5489349331200 is a wasteful number, since it uses less digits than its factorization.

5489349331200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 147762 (or 147743 counting only the distinct ones).

The product of its (nonzero) digits is 2799360, while the sum is 51.

The spelling of 5489349331200 in words is "five trillion, four hundred eighty-nine billion, three hundred forty-nine million, three hundred thirty-one thousand, two hundred".