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55001010513 = 319964930009
BaseRepresentation
bin110011001110010100…
…001101000101010001
312020222010002211100110
4303032110031011101
51400120224314023
641133410311533
73654655606221
oct631624150521
9166863084313
1055001010513
1121364700299
12a7ab8885a9
135256b93547
14293a9b6081
15166d94aa93
hexcce50d151

55001010513 has 8 divisors (see below), whose sum is σ = 77194400800. Its totient is φ = 34737480288.

The previous prime is 55001010511. The next prime is 55001010523. The reversal of 55001010513 is 31501010055.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 55001010513 - 21 = 55001010511 is a prime.

It is a super-2 number, since 2×550010105132 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 55001010513.

It is not an unprimeable number, because it can be changed into a prime (55001010511) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 482464948 + ... + 482465061.

It is an arithmetic number, because the mean of its divisors is an integer number (9649300100).

Almost surely, 255001010513 is an apocalyptic number.

It is an amenable number.

55001010513 is a deficient number, since it is larger than the sum of its proper divisors (22193390287).

55001010513 is a wasteful number, since it uses less digits than its factorization.

55001010513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 964930031.

The product of its (nonzero) digits is 375, while the sum is 21.

Adding to 55001010513 its reverse (31501010055), we get a palindrome (86502020568).

The spelling of 55001010513 in words is "fifty-five billion, one million, ten thousand, five hundred thirteen".

Divisors: 1 3 19 57 964930009 2894790027 18333670171 55001010513