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55111311311155 = 5114361382014427
BaseRepresentation
bin11001000011111100110100…
…01000100100000100110011
321020010120221001010212122221
430201332122020210010303
524210420431143424110
6313113441545341511
714415442445624311
oct1441763210440463
9236116831125587
1055111311311155
1116618637539190
126220b36797897
132499c8887c6a8
14d8758a39b0b1
156588896507da
hex321f9a224133

55111311311155 has 32 divisors (see below), whose sum is σ = 75033745890048. Its totient is φ = 38507054140800.

The previous prime is 55111311311027. The next prime is 55111311311171.

It can be divided in two parts, 5511131 and 1311155, that added together give a palindrome (6822286).

55111311311155 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 55111311311155 - 27 = 55111311311027 is a prime.

It is a super-3 number, since 3×551113113111553 (a number of 42 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 55111311311155.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 190862949 + ... + 191151478.

It is an arithmetic number, because the mean of its divisors is an integer number (2344804559064).

Almost surely, 255111311311155 is an apocalyptic number.

55111311311155 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

55111311311155 is a deficient number, since it is larger than the sum of its proper divisors (19922434578893).

55111311311155 is a wasteful number, since it uses less digits than its factorization.

55111311311155 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 382014547.

The product of its digits is 5625, while the sum is 34.

The spelling of 55111311311155 in words is "fifty-five trillion, one hundred eleven billion, three hundred eleven million, three hundred eleven thousand, one hundred fifty-five".