Base | Representation |
---|---|
bin | 11001000100001111010011… |
… | …01010010110110001100111 |
3 | 21020011112112200021010020110 |
4 | 30202013221222112301213 |
5 | 24211101242242113411 |
6 | 313122202423304103 |
7 | 14416243413105651 |
oct | 1442075152266147 |
9 | 236145480233213 |
10 | 55121235504231 |
11 | 1662186a486346 |
12 | 6222a462ab033 |
13 | 249abaa9471a0 |
14 | d87c4c4296d1 |
15 | 658c6aa372a6 |
hex | 3221e9a96c67 |
55121235504231 has 16 divisors (see below), whose sum is σ = 79148578642560. Its totient is φ = 33920701202400.
The previous prime is 55121235504221. The next prime is 55121235504233. The reversal of 55121235504231 is 13240553212155.
55121235504231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 55121235504231 - 214 = 55121235487847 is a prime.
It is a super-2 number, since 2×551212355042312 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a self number, because there is not a number n which added to its sum of digits gives 55121235504231.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55121235504233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34731400 + ... + 36283778.
It is an arithmetic number, because the mean of its divisors is an integer number (4946786165160).
Almost surely, 255121235504231 is an apocalyptic number.
55121235504231 is a deficient number, since it is larger than the sum of its proper divisors (24027343138329).
55121235504231 is a wasteful number, since it uses less digits than its factorization.
55121235504231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2462846.
The product of its (nonzero) digits is 180000, while the sum is 39.
Adding to 55121235504231 its reverse (13240553212155), we get a palindrome (68361788716386).
The spelling of 55121235504231 in words is "fifty-five trillion, one hundred twenty-one billion, two hundred thirty-five million, five hundred four thousand, two hundred thirty-one".
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