Base | Representation |
---|---|
bin | 110011100010101101… |
… | …000110001101011011 |
3 | 12021211221202202212012 |
4 | 303202231012031123 |
5 | 1401320312032113 |
6 | 41231350140135 |
7 | 3666311264201 |
oct | 634255061533 |
9 | 167757682765 |
10 | 55343080283 |
11 | 2151a7a9387 |
12 | a88635164b |
13 | 52aca00caa |
14 | 29701bb071 |
15 | 168d9b9aa8 |
hex | ce2b4635b |
55343080283 has 2 divisors, whose sum is σ = 55343080284. Its totient is φ = 55343080282.
The previous prime is 55343080279. The next prime is 55343080337. The reversal of 55343080283 is 38208034355.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55343080283 - 22 = 55343080279 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 55343080283.
It is not a weakly prime, because it can be changed into another prime (55343080783) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27671540141 + 27671540142.
It is an arithmetic number, because the mean of its divisors is an integer number (27671540142).
Almost surely, 255343080283 is an apocalyptic number.
55343080283 is a deficient number, since it is larger than the sum of its proper divisors (1).
55343080283 is an equidigital number, since it uses as much as digits as its factorization.
55343080283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 345600, while the sum is 41.
The spelling of 55343080283 in words is "fifty-five billion, three hundred forty-three million, eighty thousand, two hundred eighty-three".
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