Base | Representation |
---|---|
bin | 11001001110110001111100… |
… | …10101110100110011110111 |
3 | 21021110011102212120120200001 |
4 | 30213120332111310303313 |
5 | 24233020032430012310 |
6 | 314000423142132131 |
7 | 14454355126542451 |
oct | 1447307625646367 |
9 | 237404385516601 |
10 | 55483433438455 |
11 | 167514347a9170 |
12 | 6281089721047 |
13 | 24c60b0690269 |
14 | d9b5abcc12d1 |
15 | 6633b88a893a |
hex | 32763e574cf7 |
55483433438455 has 16 divisors (see below), whose sum is σ = 72633578296608. Its totient is φ = 40351187968000.
The previous prime is 55483433438399. The next prime is 55483433438467.
55483433438455 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 55483433438455 - 243 = 46687340416247 is a prime.
It is a super-2 number, since 2×554834334384552 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 656775 + ... + 10554535.
It is an arithmetic number, because the mean of its divisors is an integer number (4539598643538).
Almost surely, 255483433438455 is an apocalyptic number.
55483433438455 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55483433438455 is a deficient number, since it is larger than the sum of its proper divisors (17150144858153).
55483433438455 is a wasteful number, since it uses less digits than its factorization.
55483433438455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9999698.
The product of its digits is 829440000, while the sum is 64.
The spelling of 55483433438455 in words is "fifty-five trillion, four hundred eighty-three billion, four hundred thirty-three million, four hundred thirty-eight thousand, four hundred fifty-five".
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