Base | Representation |
---|---|
bin | 10000010101001011000… |
… | …10011000001001101101 |
3 | 1222122100121220212200012 |
4 | 20022211202120021231 |
5 | 33143134442012231 |
6 | 1105435405143005 |
7 | 55353102545306 |
oct | 10124542301155 |
9 | 1878317825605 |
10 | 561123000941 |
11 | 1a6a7533a808 |
12 | 908bab5aa65 |
13 | 40bb544cc59 |
14 | 1d230cc17ad |
15 | e8e1c61e2b |
hex | 82a589826d |
561123000941 has 2 divisors, whose sum is σ = 561123000942. Its totient is φ = 561123000940.
The previous prime is 561123000929. The next prime is 561123000961. The reversal of 561123000941 is 149000321165.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 535781544841 + 25341456100 = 731971^2 + 159190^2 .
It is a cyclic number.
It is not a de Polignac number, because 561123000941 - 210 = 561122999917 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 561123000898 and 561123000907.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (561123000961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 280561500470 + 280561500471.
It is an arithmetic number, because the mean of its divisors is an integer number (280561500471).
Almost surely, 2561123000941 is an apocalyptic number.
It is an amenable number.
561123000941 is a deficient number, since it is larger than the sum of its proper divisors (1).
561123000941 is an equidigital number, since it uses as much as digits as its factorization.
561123000941 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 32.
The spelling of 561123000941 in words is "five hundred sixty-one billion, one hundred twenty-three million, nine hundred forty-one", and thus it is an aban number.
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