561123000943 has 8 divisors (see below), whose sum is σ = 564090800000.
Its totient is φ = 558159234048.
The previous prime is 561123000941. The next prime is 561123000961. The reversal of 561123000943 is 349000321165.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 561123000943 - 21 = 561123000941 is a prime.
It is a house number.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 561123000899 and 561123000908.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (561123000941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 728778 + ... + 1285831.
It is an arithmetic number, because the mean of its divisors is an integer number (70511350000).
Almost surely, 2561123000943 is an apocalyptic number.
561123000943 is a deficient number, since it is larger than the sum of its proper divisors (2967799057).
561123000943 is a wasteful number, since it uses less digits than its factorization.
561123000943 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2016081.
The product of its (nonzero) digits is 19440, while the sum is 34.
The spelling of 561123000943 in words is "five hundred sixty-one billion, one hundred twenty-three million, nine hundred forty-three", and thus it is an aban number.