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561123000943 = 22312492014609
BaseRepresentation
bin10000010101001011000…
…10011000001001101111
31222122100121220212200021
420022211202120021233
533143134442012233
61105435405143011
755353102545311
oct10124542301157
91878317825607
10561123000943
111a6a7533a80a
12908bab5aa67
1340bb544cc5b
141d230cc17b1
15e8e1c61e2d
hex82a589826f

561123000943 has 8 divisors (see below), whose sum is σ = 564090800000. Its totient is φ = 558159234048.

The previous prime is 561123000941. The next prime is 561123000961. The reversal of 561123000943 is 349000321165.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 561123000943 - 21 = 561123000941 is a prime.

It is a house number.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 561123000899 and 561123000908.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (561123000941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 728778 + ... + 1285831.

It is an arithmetic number, because the mean of its divisors is an integer number (70511350000).

Almost surely, 2561123000943 is an apocalyptic number.

561123000943 is a deficient number, since it is larger than the sum of its proper divisors (2967799057).

561123000943 is a wasteful number, since it uses less digits than its factorization.

561123000943 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2016081.

The product of its (nonzero) digits is 19440, while the sum is 34.

The spelling of 561123000943 in words is "five hundred sixty-one billion, one hundred twenty-three million, nine hundred forty-three", and thus it is an aban number.

Divisors: 1 223 1249 278527 2014609 449257807 2516246641 561123000943