Base | Representation |
---|---|
bin | 101001000010011100100… |
… | …1100110010001100110011 |
3 | 201222012110211200000202221 |
4 | 1102010321030302030303 |
5 | 1214402213414243212 |
6 | 15555032412421511 |
7 | 1121331460344112 |
oct | 122047114621463 |
9 | 21865424600687 |
10 | 5640251712307 |
11 | 18850210612a3 |
12 | 771150a77897 |
13 | 31bb47c95c04 |
14 | 156dbd7dbc79 |
15 | 9bab11e7807 |
hex | 52139332333 |
5640251712307 has 8 divisors (see below), whose sum is σ = 5790415491072. Its totient is φ = 5491344534600.
The previous prime is 5640251712287. The next prime is 5640251712311. The reversal of 5640251712307 is 7032171520465.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5640251712307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5640251712367) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 314141169 + ... + 314159122.
It is an arithmetic number, because the mean of its divisors is an integer number (723801936384).
Almost surely, 25640251712307 is an apocalyptic number.
5640251712307 is a deficient number, since it is larger than the sum of its proper divisors (150163778765).
5640251712307 is a wasteful number, since it uses less digits than its factorization.
5640251712307 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 628300529.
The product of its (nonzero) digits is 352800, while the sum is 43.
The spelling of 5640251712307 in words is "five trillion, six hundred forty billion, two hundred fifty-one million, seven hundred twelve thousand, three hundred seven".
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