Base | Representation |
---|---|
bin | 111101000001010110… |
… | …110001111010110101 |
3 | 20021010021022200010001 |
4 | 331001112301322311 |
5 | 2033141334000432 |
6 | 50033330231301 |
7 | 4506446211646 |
oct | 750126617265 |
9 | 207107280101 |
10 | 65521000117 |
11 | 25872995181 |
12 | 10846a25531 |
13 | 6242514571 |
14 | 3257c156cd |
15 | 1a872be9e7 |
hex | f415b1eb5 |
65521000117 has 16 divisors (see below), whose sum is σ = 67527536112. Its totient is φ = 63527293440.
The previous prime is 65521000063. The next prime is 65521000141. The reversal of 65521000117 is 71100012556.
It can be written as a sum of positive squares in 8 ways, for example, as 5948882641 + 59572117476 = 77129^2 + 244074^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-65521000117 is a prime.
It is a deceptive number, since it divides R65521000116.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (65521000147) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14127723 + ... + 14132359.
It is an arithmetic number, because the mean of its divisors is an integer number (4220471007).
Almost surely, 265521000117 is an apocalyptic number.
It is an amenable number.
65521000117 is a deficient number, since it is larger than the sum of its proper divisors (2006535995).
65521000117 is a wasteful number, since it uses less digits than its factorization.
65521000117 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5928.
The product of its (nonzero) digits is 2100, while the sum is 28.
The spelling of 65521000117 in words is "sixty-five billion, five hundred twenty-one million, one hundred seventeen", and thus it is an aban number.
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