Base | Representation |
---|---|

bin | 101011001111111… |

… | …011000000000001 |

3 | 1212120100000000001 |

4 | 223033323000001 |

5 | 2441223002423 |

6 | 200000000001 |

7 | 23660306506 |

oct | 5317730001 |

9 | 1776300001 |

10 | 725594113 |

11 | 342640662 |

12 | 183000001 |

13 | b7430b3a |

14 | 6c51b4ad |

15 | 43a7acad |

hex | 2b3fb001 |

725594113 has 2 divisors, whose sum is σ = 725594114. Its totient is φ = 725594112.

The previous prime is 725594081. The next prime is 725594117. The reversal of 725594113 is 311495527.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 702091009 + 23503104 = 26497^2 + 4848^2 .

It is a cyclic number.

It is not a de Polignac number, because 725594113 - 2^{5} = 725594081 is a prime.

It is not a weakly prime, because it can be changed into another prime (725594117) by changing a digit.

It is a Pierpont prime, being equal to 2^{12} ⋅ 3^{11} + 1.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 362797056 + 362797057.

It is an arithmetic number, because the mean of its divisors is an integer number (362797057).

Almost surely, 2^{725594113} is an apocalyptic number.

It is an amenable number.

725594113 is a deficient number, since it is larger than the sum of its proper divisors (1).

725594113 is an equidigital number, since it uses as much as digits as its factorization.

725594113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 37800, while the sum is 37.

The square root of 725594113 is about 26936.8541778731. The cubic root of 725594113 is about 898.5962119712.

The spelling of 725594113 in words is "seven hundred twenty-five million, five hundred ninety-four thousand, one hundred thirteen".

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