79994000113 has 4 divisors (see below), whose sum is σ = 82752413940. Its totient is φ = 77235586288.

The previous prime is 79994000087. The next prime is 79994000143. The reversal of 79994000113 is 31100049997.

79994000113 = 199992² + 199993².

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31100049997 = 419 ⋅74224463.

It can be written as a sum of positive squares in 2 ways, for example, as 39996800064 + 39997200049 = 199992^2 + 199993^2 .

It is a cyclic number.

It is not a de Polignac number, because 79994000113 - 2¹⁷ = 79993869041 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 79994000113.

It is not an unprimeable number, because it can be changed into a prime (79994000143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1379206870 + ... + 1379206927.

It is an arithmetic number, because the mean of its divisors is an integer number (20688103485).

Almost surely, 2^79994000113 is an apocalyptic number.

79994000113 is the 199993-rd centered square number.

It is an amenable number.

79994000113 is a deficient number, since it is larger than the sum of its proper divisors (2758413827).

79994000113 is a wasteful number, since it uses less digits than its factorization.

79994000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2758413826.

The product of its (nonzero) digits is 61236, while the sum is 43.

The spelling of 79994000113 in words is "seventy-nine billion, nine hundred ninety-four million, one hundred thirteen", and thus it is an aban number.