Base | Representation |
---|---|
bin | 101001110100010110… |
… | …0000110010000000101 |
3 | 22120210112121020200012 |
4 | 1103220230012100011 |
5 | 2432404111014343 |
6 | 105131030400005 |
7 | 6326256526565 |
oct | 1235054062005 |
9 | 276715536605 |
10 | 89803219973 |
11 | 350a3638375 |
12 | 154a2b00005 |
13 | 86121247ac |
14 | 44bcb16da5 |
15 | 2508e5b718 |
hex | 14e8b06405 |
89803219973 has 2 divisors, whose sum is σ = 89803219974. Its totient is φ = 89803219972.
The previous prime is 89803219963. The next prime is 89803220033. The reversal of 89803219973 is 37991230898.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 78588833569 + 11214386404 = 280337^2 + 105898^2 .
It is a cyclic number.
It is not a de Polignac number, because 89803219973 - 210 = 89803218949 is a prime.
It is a super-2 number, since 2×898032199732 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (89803219943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 44901609986 + 44901609987.
It is an arithmetic number, because the mean of its divisors is an integer number (44901609987).
Almost surely, 289803219973 is an apocalyptic number.
It is an amenable number.
89803219973 is a deficient number, since it is larger than the sum of its proper divisors (1).
89803219973 is an equidigital number, since it uses as much as digits as its factorization.
89803219973 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5878656, while the sum is 59.
The spelling of 89803219973 in words is "eighty-nine billion, eight hundred three million, two hundred nineteen thousand, nine hundred seventy-three".
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