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915525000001 is a prime number
BaseRepresentation
bin11010101001010011000…
…10101101101101000001
310020112010111210210112101
431110221202231231001
5104444443400000001
61540330354030401
7123100364046133
oct15245142555501
93215114723471
10915525000001
113232a9aa4107
12129527578401
1368445001441
143245122d053
1518c35496a01
hexd5298adb41

915525000001 has 2 divisors, whose sum is σ = 915525000002. Its totient is φ = 915525000000.

The previous prime is 915524999989. The next prime is 915525000007. The reversal of 915525000001 is 100000525519.

It is the 390625-th star number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 665700969025 + 249824030976 = 815905^2 + 499824^2 .

It is a cyclic number.

It is not a de Polignac number, because 915525000001 - 25 = 915524999969 is a prime.

It is a super-3 number, since 3×9155250000013 (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (915525000007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 457762500000 + 457762500001.

It is an arithmetic number, because the mean of its divisors is an integer number (457762500001).

Almost surely, 2915525000001 is an apocalyptic number.

It is an amenable number.

915525000001 is a deficient number, since it is larger than the sum of its proper divisors (1).

915525000001 is an equidigital number, since it uses as much as digits as its factorization.

915525000001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2250, while the sum is 28.

The spelling of 915525000001 in words is "nine hundred fifteen billion, five hundred twenty-five million, one", and thus it is an aban number.