Base | Representation |
---|---|
bin | 101010101001101011… |
… | …1100100010010110001 |
3 | 22202102021101111110112 |
4 | 1111103113210102301 |
5 | 3000040302000423 |
6 | 110024403511105 |
7 | 6421521440516 |
oct | 1252327442261 |
9 | 282367344415 |
10 | 91593000113 |
11 | 3593195170a |
12 | 15902388495 |
13 | 8838b76bb4 |
14 | 460c6cd30d |
15 | 25b1146a78 |
hex | 15535e44b1 |
91593000113 has 2 divisors, whose sum is σ = 91593000114. Its totient is φ = 91593000112.
The previous prime is 91593000041. The next prime is 91593000131. The reversal of 91593000113 is 31100039519.
It is a happy number.
Together with next prime (91593000131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 59762158369 + 31830841744 = 244463^2 + 178412^2 .
It is a cyclic number.
It is not a de Polignac number, because 91593000113 - 230 = 90519258289 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 91593000113.
It is a weakly prime.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45796500056 + 45796500057.
It is an arithmetic number, because the mean of its divisors is an integer number (45796500057).
Almost surely, 291593000113 is an apocalyptic number.
It is an amenable number.
91593000113 is a deficient number, since it is larger than the sum of its proper divisors (1).
91593000113 is an equidigital number, since it uses as much as digits as its factorization.
91593000113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3645, while the sum is 32.
The spelling of 91593000113 in words is "ninety-one billion, five hundred ninety-three million, one hundred thirteen", and thus it is an aban number.
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