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9250000003 is a prime number
BaseRepresentation
bin10001001110101011…
…11100110010000011
3212212122111200112201
420213111330302003
5122421000000003
64125511334031
7445136463016
oct104725746203
925778450481
109250000003
113a17424a02
121961981317
13b454c29aa
1463a6d137d
15392110b1d
hex22757cc83

9250000003 has 2 divisors, whose sum is σ = 9250000004. Its totient is φ = 9250000002.

The previous prime is 9249999971. The next prime is 9250000009. The reversal of 9250000003 is 3000000529.

9250000003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 9250000003 - 25 = 9249999971 is a prime.

It is not a weakly prime, because it can be changed into another prime (9250000009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4625000001 + 4625000002.

It is an arithmetic number, because the mean of its divisors is an integer number (4625000002).

Almost surely, 29250000003 is an apocalyptic number.

9250000003 is a deficient number, since it is larger than the sum of its proper divisors (1).

9250000003 is an equidigital number, since it uses as much as digits as its factorization.

9250000003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 270, while the sum is 19.

The square root of 9250000003 is about 96176.9203239530. The cubic root of 9250000003 is about 2099.1682271311.

The spelling of 9250000003 in words is "nine billion, two hundred fifty million, three", and thus it is an aban number.