993000000399 has 32 divisors (see below), whose sum is σ = 1458088819200. Its totient is φ = 596106255360.

The previous prime is 993000000397. The next prime is 993000000439.

993000000399 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 993000000399 - 2¹ = 993000000397 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 993000000399.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (993000000397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5728107 + ... + 5898915.

It is an arithmetic number, because the mean of its divisors is an integer number (45565275600).

Almost surely, 2^993000000399 is an apocalyptic number.

993000000399 is a deficient number, since it is larger than the sum of its proper divisors (465088818801).

993000000399 is a wasteful number, since it uses less digits than its factorization.

993000000399 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 172495.

The product of its (nonzero) digits is 59049, while the sum is 42.

It can be divided in two parts, 993000000 and 399, that added together give a palindrome (993000399).

The spelling of 993000000399 in words is "nine hundred ninety-three billion, three hundred ninety-nine", and thus it is an aban number.