9955507 has 2 divisors, whose sum is σ = 9955508. Its totient is φ = 9955506.

The previous prime is 9955499. The next prime is 9955511. The reversal of 9955507 is 7055599.

It is a strong prime.

It is an emirp because it is prime and its reverse (7055599) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9955507 - 2³ = 9955499 is a prime.

It is a super-2 number, since 2×9955507² = 198224239254098, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 9955507.

It is not a weakly prime, because it can be changed into another prime (9955567) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4977753 + 4977754.

It is an arithmetic number, because the mean of its divisors is an integer number (4977754).

Almost surely, 2^9955507 is an apocalyptic number.

9955507 is a deficient number, since it is larger than the sum of its proper divisors (1).

9955507 is an equidigital number, since it uses as much as digits as its factorization.

9955507 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 70875, while the sum is 40.

The square root of 9955507 is about 3155.2348565519. The cubic root of 9955507 is about 215.1234697331.

The spelling of 9955507 in words is "nine million, nine hundred fifty-five thousand, five hundred seven".