Base | Representation |
---|---|
bin | 101110100000110001… |
… | …1001110010110110101 |
3 | 100112211002100222010002 |
4 | 1131001203032112311 |
5 | 3114030301010233 |
6 | 113515220441045 |
7 | 10134134666051 |
oct | 1350143162665 |
9 | 315732328102 |
10 | 99884000693 |
11 | 393a6a07104 |
12 | 17436b49185 |
13 | 955a7867b9 |
14 | 4b978a6c61 |
15 | 28e8e746e8 |
hex | 17418ce5b5 |
99884000693 has 2 divisors, whose sum is σ = 99884000694. Its totient is φ = 99884000692.
The previous prime is 99884000639. The next prime is 99884000707. The reversal of 99884000693 is 39600048899.
Together with previous prime (99884000639) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 62001996004 + 37882004689 = 249002^2 + 194633^2 .
It is a cyclic number.
It is not a de Polignac number, because 99884000693 - 210 = 99883999669 is a prime.
It is a congruent number.
It is a weakly prime.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49942000346 + 49942000347.
It is an arithmetic number, because the mean of its divisors is an integer number (49942000347).
Almost surely, 299884000693 is an apocalyptic number.
It is an amenable number.
99884000693 is a deficient number, since it is larger than the sum of its proper divisors (1).
99884000693 is an equidigital number, since it uses as much as digits as its factorization.
99884000693 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3359232, while the sum is 56.
The spelling of 99884000693 in words is "ninety-nine billion, eight hundred eighty-four million, six hundred ninety-three", and thus it is an aban number.
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