Base | Representation |
---|---|
bin | 11101000100110101011… |
… | …01011000011011010111 |
3 | 10112111122222102201210111 |
4 | 32202122231120123113 |
5 | 112332002132003341 |
6 | 2042540325103451 |
7 | 132114562615114 |
oct | 16423255303327 |
9 | 3474588381714 |
10 | 999028000471 |
11 | 35575a2972a6 |
12 | 141750557b87 |
13 | 73291ab34a7 |
14 | 364d330790b |
15 | 1aec1266681 |
hex | e89ab586d7 |
999028000471 has 2 divisors, whose sum is σ = 999028000472. Its totient is φ = 999028000470.
The previous prime is 999028000367. The next prime is 999028000519. The reversal of 999028000471 is 174000820999.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 999028000471 - 225 = 998994446039 is a prime.
It is a super-3 number, since 3×9990280004713 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (999028001471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499514000235 + 499514000236.
It is an arithmetic number, because the mean of its divisors is an integer number (499514000236).
Almost surely, 2999028000471 is an apocalyptic number.
999028000471 is a deficient number, since it is larger than the sum of its proper divisors (1).
999028000471 is an equidigital number, since it uses as much as digits as its factorization.
999028000471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 326592, while the sum is 49.
The spelling of 999028000471 in words is "nine hundred ninety-nine billion, twenty-eight million, four hundred seventy-one", and thus it is an aban number.
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