Base | Representation |
---|---|
bin | 111011100100010… |
… | …101100001111001 |
3 | 2120122111211011022 |
4 | 323210111201321 |
5 | 4021320143423 |
6 | 243100112225 |
7 | 33523412363 |
oct | 7344254171 |
9 | 2518454138 |
10 | 999381113 |
11 | 473140905 |
12 | 23a835675 |
13 | 12c081593 |
14 | 96a29d33 |
15 | 5cb0cdc8 |
hex | 3b915879 |
999381113 has 2 divisors, whose sum is σ = 999381114. Its totient is φ = 999381112.
The previous prime is 999381077. The next prime is 999381139. The reversal of 999381113 is 311183999.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 917605264 + 81775849 = 30292^2 + 9043^2 .
It is a cyclic number.
It is not a de Polignac number, because 999381113 - 26 = 999381049 is a prime.
It is a super-2 number, since 2×9993811132 = 1997525218042237538, which contains 22 as substring.
It is a Chen prime.
It is equal to p50817878 and since 999381113 and 50817878 have the same sum of digits, it is a Honaker prime.
It is not a weakly prime, because it can be changed into another prime (999381013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499690556 + 499690557.
It is an arithmetic number, because the mean of its divisors is an integer number (499690557).
Almost surely, 2999381113 is an apocalyptic number.
It is an amenable number.
999381113 is a deficient number, since it is larger than the sum of its proper divisors (1).
999381113 is an equidigital number, since it uses as much as digits as its factorization.
999381113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 52488, while the sum is 44.
The square root of 999381113 is about 31612.9896245199. The cubic root of 999381113 is about 999.7936617608.
The spelling of 999381113 in words is "nine hundred ninety-nine million, three hundred eighty-one thousand, one hundred thirteen".
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