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999996000000 = 28356167499
BaseRepresentation
bin11101000110101000110…
…10000000011100000000
310112121011102220012111220
432203110122000130000
5112340442434000000
62043220344435040
7132150555516144
oct16432432003400
93477142805456
10999996000000
11356106743708
12141980778a80
13733b74c7c8a
1436585ac5224
151b02b2261a0
hexe8d4680700

999996000000 has 504 divisors, whose sum is σ = 3353394576000. Its totient is φ = 264537600000.

The previous prime is 999995999993. The next prime is 999996000001. The reversal of 999996000000 is 699999.

It is a nialpdrome in base 10.

It is a junction number, because it is equal to n+sod(n) for n = 999995999898 and 999995999907.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (999996000001) by changing a digit.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 2003999751 + ... + 2004000249.

Almost surely, 2999996000000 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 999996000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1676697288000).

999996000000 is an abundant number, since it is smaller than the sum of its proper divisors (2353398576000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

999996000000 is an frugal number, since it uses more digits than its factorization.

999996000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 715 (or 676 counting only the distinct ones).

The product of its (nonzero) digits is 354294, while the sum is 51.

Adding to 999996000000 its reverse (699999), we get a palindrome (999996699999).

The spelling of 999996000000 in words is "nine hundred ninety-nine billion, nine hundred ninety-six million", and thus it is an aban number.