999999000943 has 2 divisors, whose sum is σ = 999999000944. Its totient is φ = 999999000942.

The previous prime is 999999000929. The next prime is 999999000961. The reversal of 999999000943 is 349000999999.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-999999000943 is a prime.

It is a super-2 number, since 2×999999000943² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (999999000743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499999500471 + 499999500472.

It is an arithmetic number, because the mean of its divisors is an integer number (499999500472).

Almost surely, 2^999999000943 is an apocalyptic number.

999999000943 is a deficient number, since it is larger than the sum of its proper divisors (1).

999999000943 is an equidigital number, since it uses as much as digits as its factorization.

999999000943 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 57395628, while the sum is 70.

The spelling of 999999000943 in words is "nine hundred ninety-nine billion, nine hundred ninety-nine million, nine hundred forty-three", and thus it is an aban number.