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999999949013969 is a prime number
BaseRepresentation
bin1110001101011111101010000…
…1101111001000001111010001
311212010201001122211012221011112
43203113322201233020033101
52022032444343421421334
613502453345022423105
7420430416646640261
oct34327724157101721
94763631584187145
10999999949013969
1126a6a3662301022
12941a6833731a95
1333bca78a615517
14138d2381c037a1
157a92460ac94ce
hex38d7ea1bc83d1

999999949013969 has 2 divisors, whose sum is σ = 999999949013970. Its totient is φ = 999999949013968.

The previous prime is 999999949013959. The next prime is 999999949013971. The reversal of 999999949013969 is 969310949999999.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 996777608086225 + 3222340927744 = 31571785^2 + 1795088^2 .

It is a cyclic number.

It is not a de Polignac number, because 999999949013969 - 216 = 999999948948433 is a prime.

It is a super-2 number, since 2×9999999490139692 (a number of 31 digits) contains 22 as substring.

Together with 999999949013971, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (999999949013959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499999974506984 + 499999974506985.

It is an arithmetic number, because the mean of its divisors is an integer number (499999974506985).

Almost surely, 2999999949013969 is an apocalyptic number.

It is an amenable number.

999999949013969 is a deficient number, since it is larger than the sum of its proper divisors (1).

999999949013969 is an equidigital number, since it uses as much as digits as its factorization.

999999949013969 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 251048476872, while the sum is 104.

The spelling of 999999949013969 in words is "nine hundred ninety-nine trillion, nine hundred ninety-nine billion, nine hundred forty-nine million, thirteen thousand, nine hundred sixty-nine".