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10000112113 = 17588241889
BaseRepresentation
bin10010101000000110…
…11001100111110001
3221210220222022220201
421110003121213301
5130440012041423
64332145035201
7502545356545
oct112403314761
927726868821
1010000112113
114271891272
121b31025b01
13c34a29504
146ac191a25
153d7dd12ad
hex2540d99f1

10000112113 has 4 divisors (see below), whose sum is σ = 10588354020. Its totient is φ = 9411870208.

The previous prime is 10000112099. The next prime is 10000112117. The reversal of 10000112113 is 31121100001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3867969249 + 6132142864 = 62193^2 + 78308^2 .

It is a de Polignac number, because none of the positive numbers 2k-10000112113 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10000112113.

It is not an unprimeable number, because it can be changed into a prime (10000112117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 294120928 + ... + 294120961.

It is an arithmetic number, because the mean of its divisors is an integer number (2647088505).

Almost surely, 210000112113 is an apocalyptic number.

It is an amenable number.

10000112113 is a deficient number, since it is larger than the sum of its proper divisors (588241907).

10000112113 is an equidigital number, since it uses as much as digits as its factorization.

10000112113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 588241906.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 10000112113 its reverse (31121100001), we get a palindrome (41121212114).

The spelling of 10000112113 in words is "ten billion, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 17 588241889 10000112113