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10000153 = 27913583
BaseRepresentation
bin100110001001…
…011100011001
3200211001122001
4212021130121
510030001103
6554201001
7150666652
oct46113431
920731561
1010000153
115710299
123423161
1320c1967
141484529
15d2801d
hex989719

10000153 has 4 divisors (see below), whose sum is σ = 10006528. Its totient is φ = 9993780.

The previous prime is 10000141. The next prime is 10000169. The reversal of 10000153 is 35100001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 35100001 = 231526087.

It is a cyclic number.

It is not a de Polignac number, because 10000153 - 25 = 10000121 is a prime.

It is an Ulam number.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10000103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1000 + ... + 4582.

It is an arithmetic number, because the mean of its divisors is an integer number (2501632).

Almost surely, 210000153 is an apocalyptic number.

It is an amenable number.

10000153 is a deficient number, since it is larger than the sum of its proper divisors (6375).

10000153 is an equidigital number, since it uses as much as digits as its factorization.

10000153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6374.

The product of its (nonzero) digits is 15, while the sum is 10.

The square root of 10000153 is about 3162.3018514999. The cubic root of 10000153 is about 215.4445677593. Note that the first 3 decimals are identical.

Adding to 10000153 its reverse (35100001), we get a palindrome (45100154).

It can be divided in two parts, 10000 and 153, that added together give a triangular number (10153 = T142).

The spelling of 10000153 in words is "ten million, one hundred fifty-three", and thus it is an aban number.

Divisors: 1 2791 3583 10000153